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x^2+28x+187=391
We move all terms to the left:
x^2+28x+187-(391)=0
We add all the numbers together, and all the variables
x^2+28x-204=0
a = 1; b = 28; c = -204;
Δ = b2-4ac
Δ = 282-4·1·(-204)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-40}{2*1}=\frac{-68}{2} =-34 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+40}{2*1}=\frac{12}{2} =6 $
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